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. 2002 Aug 6;99(16):10533-8.
doi: 10.1073/pnas.152011499. Epub 2002 Jul 29.

Sympatric speciation by sexual conflict

Affiliations

Sympatric speciation by sexual conflict

Sergey Gavrilets et al. Proc Natl Acad Sci U S A. .

Abstract

It is well established that sexual conflict can drive an endless coevolutionary chase between the sexes potentially leading to genetic divergence of isolated populations and allopatric speciation. We present a simple mathematical model that shows that sexual conflict over mating rate can result in two other general regimes. First, rather than "running away" from males, females can diversify genetically into separate groups, effectively "trapping" the males in the middle at a state characterized by reduced mating success. Female diversification brings coevolutionary chase to the end. Second, under certain conditions, males respond to female diversification by diversifying themselves. This response results in the formation of reproductively isolated clusters of genotypes that emerge sympatrically.

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Figures

Fig 1.
Fig 1.
Endless coevolutionary chase between the sexes. Parameters: μ = 10−5, r = 0.5, Δ = 10−6, vm,j = 1, Ψij = exp[−(ij)2/(2α2)] with α = formula image, and wf,i = exp[−S(PiPopt)2] with S = 1, Popt = 0.4. Initial genotype frequencies are Φ56 = 0.99, Φ55 = 0.01. The equilibrium value of is ≈0.86.
Fig 2.
Fig 2.
Buridan's Ass scenario. Parameters are the same as in Fig. 1 except Δ = 10−8, Popt = .6 and initial genotype frequencies are Φ23 = 0.99, Φ22 = 0.01. The equilibrium value of ≈ 0.64.
Fig 3.
Fig 3.
Sympatric speciation. Parameters are the same as in Fig. 2 except Popt = 0.4. The equilibrium value of ≈ 0.42.
Fig 4.
Fig 4.
Complex genetic structure. (a) Sympatric emergence of four species. Parameters are the same as in Fig. 3 except Popt = 0.25 and S = 0.5. ≈ 0.27. (b) Genetic diversification without distinct cluster formation. Parameters are the same as in Fig. 3, except Ψij = exp[−formula image/(2α2)], Popt = 0.7, α = 2, and initial genotype frequencies are Φ10 = 0.45, Φ−10 = 0.55. ≈ 0.71.

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