Myeloperoxidase of the leukocyte of normal blood. Nature of the prosthetic group of myeloperoxidase

Abstract

The absorption spectra of alkaline pyridine hemochrome of myeloperoxidase in its native, acid, and modified forms were similar to those of heme a, and the molar extinction coefficient of myeloperoxidase heme was very similar to that of heme a, assuming that myeloperoxidase contains only one heme. The anaerobic titration of myeloperoxidase with dithionite showed that one electron was consumed per molecule of the enzyme for its conversion to its reduced form. The EPR spectrum of myeloperoxidase indicated that the enzyme contains both high-spin heme and non-heme iron. Carbonyl reagents, such as borohydride, hydrazine, and benzhydrazide, reacted with myeloperoxidase, causing blue shifts in its absorption spectrum. The heme was labeled with a tritium of boro[3H]hydride, suggesting that the reagents reacted with a formyl group on the porphyrin ring of the myeloperoxidase heme. When hydrazine was added to cyanide complex I of myeloperoxidase the complex was converted to the hydrazine-enzyme compound. Myeloperoxidase reacted with bisulfite to form a compound with an absorption spectrum similar to that of cyanide complex I. Borohydride-treated myeloperoxidase formed only one cyanide complex, while the native enzyme formed two different cyanide complexes, I (Kd = 0.3 muM) and II (approximate Kd = 0.1 mM). The EPR spectrum indicated that cyanide complex I of myeloperoxidase still contained high-spin heme. The results suggested that cyanide complex I and the bisulfite compound of myeloperoxidase were adducts between the nucleophilic reagents and the formyl group of myeloperoxidase heme. Based on these results, we concluded that one of the two iron atoms in a myeloperoxidase molecule exists in a formyl-heme moiety similar to heme a and the other exists as a non-heme iron.